Question
There are two containers having equal quantities of
mixtures of two chemical types A and B. The 1st container contains 30% of type A chemical whereas the 2nd container contains 60% of type B chemical. If the mixtures from both the containers are mixed together, then find the percent of the type A chemical in the resultant mixture.Solution
ATQ, Let the mixture in each container be 100 litres. Quantity of type A chemical in 1st container = 100 × 30% = 30 litres. Quantity of type B chemical in 2nd container = 100 × 60% = 60 litres. Quantity of type A chemical in 2nd container = 100 – 60 = 40 litres. Quantity of final mixture = 100 + 100 = 200 litres. Quantity of type A chemical in final mixture = 30 + 40 = 70 litres. Percent of Type A chemical in final mixture = 70/200 × 100 = 35%.
[(82 × 162)/12] - 28 = ?
24 × ?2 – 11 × 4 = 1900
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
√256 * 3 – 15% of 300 + ? = 150% of 160
756 + 432 – 361 + ? = 990
[(√576 × √144) ÷ √1296]2 = ? ÷ 3
136% of 560 - 2/7 of 630 + 45% of 420 =?
Simplify: 0.6 ÷ 0.04 + 0.125 × 0.8
What will come in the place of question mark (?) in the given expression?
888 + 777 - 666 = (? + 60) X 3 + 444