Question
There are two containers having equal quantities of
mixtures of two chemical types A and B. The 1st container contains 25% of type A chemical whereas the 2nd container contains 55% of type B chemical. If the mixtures from both the containers are mixed together, then find the percent of the type A chemical in the resultant mixture.Solution
ATQ, Let the mixture in each container be 100 litres. Quantity of type A chemical in 1st container = 100 × 25% = 25 litres. Quantity of type B chemical in 2nd container = 100 × 55% = 55 litres. Quantity of type A chemical in 2nd container = 100 – 55 = 45 litres. Quantity of final mixture = 100 + 100 = 200 litres. Quantity of type A chemical in final mixture = 25 + 45 = 70 litres. Percent of Type A chemical in final mixture = 70/200 × 100 = 35%.
More Mixture Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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