Question
40 liters of a mixture contains milk and water in the
ratio of 17: 3. After the addition of some more milk, the ratio of milk to water in the resulting mixture becomes 7: 1. The quantity of milk added to it wasSolution
Initial ratio of milk to water: 17:3 in 40 liters. Milk =17/20x 40 = 34 liters Water =3/20 × 40 = 6 liters The new ratio after adding milk= 7:1 Let the new amount of milk be 34 + x. Set up the ratio equation= (34+x)/ 6 =7 34+x=42 x=42-34=8 Milk added = 8 liters.
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
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Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
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