Question
‘x’ litres of mixture ‘A’ contains juice and
water in the ratio of 3:2, respectively and (x + 20) litres of mixture ‘B’ contains juice and water in the ratio of 2:3, respectively. If both mixtures are mixed in an empty container ‘P’ then ratio of juice and water in container ‘P’ becomes 24:25, respectively then find the value of ‘x’.Solution
According to the question, [(3x/5) + (x + 20) * 2/5] / [(2x/5) + (x + 20) * 3/5] = 24/25 Or, (3x + 2x + 40) / (2x + 3x + 60) = 24/25 Or, (5x + 40) / (5x + 60) = 24/25 Or, 125x + 1000 = 120x + 1440 Or, 5x = 440 Or, x = 88
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