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    Question

    A mixture (alcohol + water) contains 60% alcohol and 80

    litres water. Find the quantity of mixture that must be removed so that the quantity of alcohol becomes 96 litres in the resultant mixture.
    A 30 litres Correct Answer Incorrect Answer
    B 40 litres Correct Answer Incorrect Answer
    C 50 litres Correct Answer Incorrect Answer
    D 60 litres Correct Answer Incorrect Answer
    E 70 litres Correct Answer Incorrect Answer

    Solution

    Initial quantity of mixture = (80/0.4) = 200 litres Initial quantity of alcohol = 0.6 ├Ч 200 = 120 litres Let the required quantity of mixture be тАШpтАЩ litres. So, 120 тИТ (6/10) ├Ч p = 96 Or, 6p = 24 ├Ч 10 Or, p = 40 Therefore, required quantity is 40 litres.

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