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Let the price of costlier sugar = x Rs. /Kg. So-net price = 40 = (2 × 24 + 3 × x) / (2 + 3). So (48 + 3x) / 5 = 40 or 48 + 3x = 200 or x = 50.67.
I. 4x2 + 9x - 9 = 0
II. 4y2 - 19y + 12 = 0
I. x − √2401 = 0
II. y2 − 2401 = 0
I. p² - 10p +21 = 0
II. q² + q -12 = 0
Equation 1: x² - 220x + 12100 = 0
Equation 2: y² - 210y + 11025 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the...
What will be the product of smaller roots of both equations.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 33x² - 186x + 240 = 0
Equation 2: 35y² - 200y + ...
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0