Question
Two metal alloys 'M' and 'N' have gold and silver in the
ratio of 5:2 and 7:3 respectively. If 112 grams of M and 150 grams of N are mixed together, then find the ratio of gold to silver in the final mixture.Solution
Quantity of gold in 112 grams 'M' = 112 × (5/7) = 80 grams
Quantity of silver in 112 grams 'M' = 112 - 80 = 32 grams
Quantity of gold in 150 grams 'N' = 150 × (7/10) = 105 grams
Quantity of silver in 150 grams 'N' = 150 - 105 = 45 grams
So, required ratio = (80 + 105) : (32 + 45) = 185 : 77
- Find the digit sum of the largest three-digit number that leaves 1 as a remainder when divided by 8, 6, and 10.
Find the sum of all the numbers between 3000 and 14000, which are divisible by 25, 30 and 40.
A school organizes a picnic for students. The cost of transportation is ₹8,000, and the food cost is ₹5,000. If there are 50 students attending the ...
X is 10 ft tall, and he notices that he casts a shadow that's 3 ft long. He then measures that the shadow cast by his school building is 30 ft long. How...
- A student mistakenly multiplied a number by 5.6 instead of 0.56. His answer exceeded the correct one by 2800. What was the original number? (Calculate appr...
Find the smallest number which when divided by 7, 9 and 12 leaves remainder 5 in each case.
If a number is increased by 30% and 12 is subtracted from it, the result is the same as 9.6 more than 30% less of the original number. What is the numbe...
Sum of squares of three consecutive numbers is 1325. Find the sum of first and third number.
A man spends 1/7 of his income on food, 3/5 of his income house rent and 1/4 of his income on clothes. If he still has Rs. 200 left with him, his income...
Manas ordered 6 Levis jeans and some additional Blackberry jeans. The price of one Levis jeans was twice that of one Blackberry jeans. When the order wa...
