Question
A mixture contains 90% milk and rest water. A man
withdrew some mixture and replaced it with same quantity of kerosene, such that the quantity of milk remaining in the mixture now is 72%. If the man wants to bring down the quantity of milk to less than 50%, then how many more times should he repeat the same process?Solution
Let the percentage of mixture withdrawn first time be ‘p%’ . ATQ; 90 × {1 − (p/100)} = 72 Or,
1 − (p/100) = 0.8 Or,
(p/100) = 0.2 So,
p = 20 So, 20% mixture is drawn every time . Now,
Quantity of milk remaining after withdrawing once more = 72 × 0.8 = 57.6 And,
Quantity of milk remaining after withdrawing once more = 57.6 × 0.8 = 46.08 So, after withdrawing two more times , the quantity of milk reaches less than 50%.
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