Question
The average of the areas of 2 similar triangles is 706.5
m2 whose perimeters are in the ratio of 6: 11. What is 20% of the difference (in m2) in areas of both triangles?Solution
The ratio of the areas of the similar triangles is (6/11)2 =36/121 Given the average area is 706.5 m², the total area is 1413 m². Let the areas be A₁ = 36x and A2 = 121x. ATQ- 36x+121x =1413 157x =1413 x =1413/157 Solving, x = 9 m². Thus, A₁ = 324 m² and A2 = 1089 m². Difference = 765 m². 20% of the difference = 153 m². So, the answer is 153 m².
Blue – green algae grow best in:
Which scheme offers a financial subsidy for constructing and modernizing cold storage units in hilly and scheduled areas?
Average loss of agricultural produce due to weeds in India is estimated to be around
An Extension agent is considered to be a:
India ranks ______ globally in milk production as per the latest data in BAHS 2024?
Pyrethrin is made up of six toxic chemicals that together constitute an insecticidal property is extracted from
What is the minimum number of farmers required to form an FPO in the plains under the scheme?
Short term loans to farmers are mainly given for the purchase of:
How many districts were assessed for risk and vulnerability by NICRA?
What is the minimum monthly pension amount provided under the Pradhan Mantri Kisan Maandhan Yojana after the age of 60?
Relevant for Exams:
