Question
The average of the areas of 2 similar triangles is 706.5
m2 whose perimeters are in the ratio of 6: 11. What is 20% of the difference (in m2) in areas of both triangles?Solution
The ratio of the areas of the similar triangles is (6/11)2 =36/121 Given the average area is 706.5 m², the total area is 1413 m². Let the areas be A₁ = 36x and A2 = 121x. ATQ- 36x+121x =1413 157x =1413 x =1413/157 Solving, x = 9 m². Thus, A₁ = 324 m² and A2 = 1089 m². Difference = 765 m². 20% of the difference = 153 m². So, the answer is 153 m².
Under the PM Mudra Yojana, which type of loan can be availed for a maximum amount of ₹50,000?
The major aim of the PM Away Yojna Gramin is to provide a pucca house with basic amenities to all rural families, who are homeless or living in kutcha o...
What is the rank of India in Gender Gap report?
The concept of diminishing marginal utility implies that:
What is the percentage of Adjusted Net Banking Credit (ANBC) that domestic banks are required to lend to the weaker section according to the lending re...
What is the new loan limit under the Kisan Credit Card (KCC) modified interest subvention scheme as announced in the Union Budget 2025–26?
Which of the following is NOT a category for the National Gopal Ratna Award?
Which of the following is the investment arm of World Bank?
Which scheme received the Gold Award for Application of Emerging Technologies for Providing Citizen Centric Services at the 26th National Conference on ...
In PMAY-G, the housing unit constructed should be in the name of ________________.
Relevant for Exams:
