Question
'Pritampur' and 'Kanpur' divide by (d - 100) km, while
'Kanpur' and 'Delhi' are distanced by (d + 150) km. Between the stations of Pritampur and Kanpur, the train travelled at 50 km/h, while between Kanpur and Delhi, it travelled at 30 km/h. Determine the value of "d" if it takes 35 hours to travel from "Pritampur" to "Delhi" via "Kanpur."Solution
ATQ, {[(d-100)/50]+[(d+150)/(50-20)]} = 35 Or,[(d-100)/50]+[(d+150)/30] = 35 Or {3(d-100)+5(d+150)}/150 = 35 Or, 3d - 300 + 5d + 750 = 5,250 Or, 8d + 450 = 5,250 Or, 8d = 4,800 Or, 'd' = 600 Therefore, required value = 'd' = 600
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (β 484 β β 256) = ?
(13)2Β - 3127 Γ· 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 Γ· 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 Γ 5 - {272 + 162 - 422}
(15 Γ 225) Γ· (45 Γ 5) + 480 = ? + 25% of 1240
β [? x 11 + (β 1296)] = 16
11 Γ 25 + 12 Γ 15 + 14 Γ 20 + 15 = ?