Train ‘A’ running with a speed of 45 km/h crosses a pole in 4 seconds. If the time taken by train ‘A’ to cross train ‘B’ running with a speed of 54 km/h and coming from the opposite direction is 13 seconds, then find the length of train B.
Speed of train A = 45 × 5/18 = 12.5 m/s Length of train A = 12.5 × 4 = 50 metres Let length of train B = ‘l’ metres Speed of train B = 54 × 5/18 = 15 m/s Relative speed if train A with respect to train B = 15 + 12.5 = 27.5 m/s So, I + 50 = 27.5 × 13 = 357.5 So, l = 307.5 metres
Statement: B < C; D ≥ E; D ≥ A; E > C ≥ F
Conclusion:
I. C > A
II. A > F
Statements:
J ≥ F = P; F > S ≥ A; S ≥ B < C
Conclusions:
I. C > A
II. B < J
Statement: A≤B ≤C>D ; E<D ;F>E
Conclusions:
I. D>A
II. E<C
Statements: Q ≤ B = S < U > M ≥ Z
Conclusion: I. U > Q II. S ≤ Z
...Which of the following symbols respectively should replace the question marks in order to make the expression V ≥ M and X ≤ H definitely true?
...Statements: P = J = W; W ≥ Y < Q; Q < Z = L
Conclusions:
I. W ≥ Z
II. W < Z
Statements: E > U > V ≥ K > F; E ≤ N = L < H
Conclusions: I. L > K II. U < H
Statements: D < O = Q > U < I ≤ R; K ≥ O = I; R > H ≥ G
Conclusions:
I. R > O
II. K > U
III. H ≥ Q
Statements: P < L = O; N = M ≤ J ≤ K; M ≤ L
Conclusions:
I. K ≥ O
II. N ≤ L
III. O ≥ N
Statements:
A < C < F; G > H = F < K < L
Conclusions:
I). G > K
II). K ≥ G