Question
When a train covered a distance of 1235km in 19 hours.
Then the average speed of a car is 4 /5 the average speed of the train. Then, what will be the distance covered by the car in 18 hours?Solution
ATQ, we can say that, Speed of the train = = 1235/19 = 65 kmph Speed of the car = 65 x (4/5) = 52 kmph Distance covered by the car = 52 x 18 = 936 km
20.06% of 359.89 - 15.95 X ? + 18.07 X 14.95 = 48.87 X 6.02
28.95% of 924.78 + 1955% of 38.99 = ?
? + 151.99 – 100.01 = 23.01 × 4.98
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
233.98 + 73 × √35.95 - ? = 275.94 ÷ 3.99
[15.87% of 599.97 + 40.08 × ?] ÷ 4.04 = 8.082.02
37.06% of 783.45 + 2125% of 51.89 = ?
2 (1/4)% of 7999.58 + {49.06% of 898.87} + √143.14 – 19.99% of 1499.63 - (52 - 41) = ?
1254.04 – 440.18 + 399.98 ÷ 10.06 = ?