Question
Train 'X' leaves Pune heading to Nagpur at 7:00 a.m. At
9:00 a.m., Train 'Y' leaves Nagpur for Pune, traveling at 70 km/h. The trains meet at 2:00 p.m. If the total distance between the two cities is 770 km, what is the speed of Train 'X'?Solution
ATQ,
Let the speed of train 'X' be x km/h Distance covered by train 'X' in the first 2 hours = 2 × x = 2x km Time both trains traveled towards each other = 2:00 p.m. - 9:00 a.m. = 5 hours So according to the question: 5 × (70 + x) = 770 - 2x → 350 + 5x = 770 - 2x → 350 + 5x + 2x = 770 → 7x = 420 → x = 60 So, speed of train 'X' = 60 km/h
More Trains Questions
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
√323.89 × (3.20) ÷ 9.02 =?
24.11% of 249.99 + √143.97 ÷ 12.02 = ?
5983.987 + 59832.999 – 598.873 = ?
(100.01% of 44.89) ÷ 14.98 = √? - √48.98
(5.013 – 30.04) = ? + 11.98% of 4799.98
(4096)1/3 × 10.11 × 11.97 ÷ 24.32 = ? + 15.022
- √81.45 + √225.60 + 49.89% of (520.43 + 22.13% of 131.45) = ?
40.024 of 54.89% of 19.9 = ? × √(2661.98/22.09)
Find the approximate value of Question mark(?) for given equation.
135.86% of 249.99 + 24.95 × 14.03 ÷ 2.01 = ?
