Question
Train A and B can cross a 300 meters long platform in
the same time. The length of Train A is 350 meters and the speed of Train B is twice the speed of Train A. If Train A crosses a bridge of the same length as of Train B in 50 seconds, then find the time (in seconds) taken by Train B to cross a tunnel 80 m long.Solution
Let speed of train A = v meters/second
And speed of train B = 2v meters/second
Let length of train B = y meters ATQ, (y + 300)/2v = (350 + 300)/v
y + 300 = 1300
y = 1000 meters Speed of train A = (350 + 1000)/50 = 27 m/sec
Speed of train B = 2 × 27 = 54 m/sec Required time = (1000 + 80)/54 = 20 sec
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
I. 3x2 = 2x2 + 9x – 20
II. 3y2 = 75
If x2 - 3x - 18 = 0 and y2 + 9y + 18 = 0, which of the following is true?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 97x² - 436x + 339 = 0
Equation 2: 103y² - 460y + 357 = 0
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
Find the coefficient of x³ in (2x − 3)⁶.
I. p2 – 2p – 15 = 0
II. q2 + 4q – 12 = 0
I. p² - 10p +21 = 0
II. q² + q -12 = 0
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