Question
Train A and B can cross a 300 meters long platform in
the same time. The length of Train A is 350 meters and the speed of Train B is twice the speed of Train A. If Train A crosses a bridge of the same length as of Train B in 50 seconds, then find the time (in seconds) taken by Train B to cross a tunnel 80 m long.Solution
Let speed of train A = v meters/second
And speed of train B = 2v meters/second
Let length of train B = y meters ATQ, (y + 300)/2v = (350 + 300)/v
y + 300 = 1300
y = 1000 meters Speed of train A = (350 + 1000)/50 = 27 m/sec
Speed of train B = 2 × 27 = 54 m/sec Required time = (1000 + 80)/54 = 20 sec
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