Question
If x2Â - 3x - 18 = 0 and y2Â + 9y
+ 18 = 0, which of the following is true?Solution
x2 - 3x - 18 = 0=> (x-6)(x+3) = 0=> x = -3, 6y2 + 9y + 18 = 0=> (y+3)(y+6) = 0=> y = -3, -6Hence x ≥ y
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