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I. 3x2 = 2x2 + 9x – 20 => x2 - 9x + 20 = 0 => x2 - 5x – 4x + 20 = 0 => x(x – 5) – 4(x – 5) = 0 => (x – 5) (x – 4) = 0 => x = 5, 4 II. 3y2 = 75 => y2 = 25 => y = -5, 5 Hence, x = y or the relationship cannot be established.
162 ÷ [51 – {29 – (9 – 6̅ ̅+̅ ̅7̅ )}]=?
[(4√ (7) +√ (7))× (7√ (7) + 6√ (7))] - 87 = ?
...(150% of 350) ÷ ? = 15
240 + 25% of 420 – 145 =? + (2.5 + 8.5) 2
If x²y² + (1/ (x2y2)) = 83, then the value of xy – 1/xy is:
1780 – 60 ÷ 4 x 80 = ?
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
25% of 12% of 1600 + 112 = ? × 4