Question
Two trucks βMβ and βNβ started simultaneously
from cities βXβ and βYβ respectively towards each other. When they met after 9 hours, truck βNβ had travelled 144 km more than truck βMβ. How much distance did truck βMβ travel in 6 hours if the total distance between X and Y is 624 km?Solution
ATQ,
Let distance travelled by truck βMβ at the time of meet = x km
So, distance travelled by truck βNβ at the time of meet = x + 144 km
According to question;
x + x + 144 = 624
Or, 2x = 480
Or, x = 240
Distance travelled by truck βMβ in 9 hours = 240 km
Speed of truck βMβ = 240 / 9 = 26.67 km/h
Distance travelled by truck βMβ in 6 hours = 26.67 Γ 6 = 160 km
3% of 842 ÷ 2% of 421 = ?
2856 ÷ 34 = ?% of 240
- Simplify:
(21 Γ 51 + 81)/(9 Γ 14 - 30) = ?
?2 = (1035 Γ· 23) Γ (1080 Γ· 24)Β
110 Γ· 5.5 + (?)3 Γ· 12 = 20(2/3)
360 Γ· 9 + 15 % of 200 + ? * 10 = 45 * β25
(26)2 = {(20% of 40% of 18200) Γ· ?} Γ 1664 Γ· 128Β
104 × 21 ÷ 13 + ? % of 300 = 320 + 22
125 + 30% of 250 + β576 = ?