Question
A train with 18 compartments of equal length takes 36
seconds to cross a pole and 45 seconds to cross a 180-metre-long platform. If 9 compartments are removed, how long would it take to cross a pole?Solution
Let the original length of the train = βdβ metres
Then, distance covered by the train in 36 seconds = βdβ metres
Distance covered by the train in 45 seconds = (d + 180) metres
So, distance covered in (45 β 36) = 9 seconds = (d + 180 β d) = 180 metres
So, speed of the train = 180 Γ· 9 = 20 m/s
So, original length of the train = 20 Γ 36 = 720 metres
After removing 9 compartments, length of the train = 720 Γ (9/18) = 360 metres
So, required time taken = 360 Γ· 20 = 18 seconds
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