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    Question

    Train β€˜A’ running with a speed of 108 km/hr crosses

    a vertical pole in 8 seconds. Find the time taken by the train β€˜A’ to cross a train β€˜B’ whose length is 130 metres less than that of train β€˜A’ and whose speed is 1/3 more than that of train β€˜A’ if both are running in opposite direction.
    A 5 seconds Correct Answer Incorrect Answer
    B 3 seconds Correct Answer Incorrect Answer
    C 4 seconds Correct Answer Incorrect Answer
    D 7 seconds Correct Answer Incorrect Answer

    Solution

    Speed of train β€˜A’ = 108 Γ— (5/18) = 30 m/sec Length of train β€˜A’ = 30 Γ— 8 = 240 metres Length of train β€˜B’ = 240 – 130 = 110 metres Speed of train β€˜B’ = 30 + (30/3) = 40 m/sec Required time taken = (240 + 110)/(30 + 40) = 350/70 = 5 seconds

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