Question
Train ‘A’ running with a speed of 108 km/hr crosses
a vertical pole in 8 seconds. Find the time taken by the train ‘A’ to cross a train ‘B’ whose length is 130 metres less than that of train ‘A’ and whose speed is 1/3 more than that of train ‘A’ if both are running in opposite direction.Solution
Speed of train ‘A’ = 108 × (5/18) = 30 m/sec Length of train ‘A’ = 30 × 8 = 240 metres Length of train ‘B’ = 240 – 130 = 110 metres Speed of train ‘B’ = 30 + (30/3) = 40 m/sec Required time taken = (240 + 110)/(30 + 40) = 350/70 = 5 seconds
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