Question
Train βAβ running with a speed of 108 km/hr crosses
a vertical pole in 8 seconds. Find the time taken by the train βAβ to cross a train βBβ whose length is 130 metres less than that of train βAβ and whose speed is 1/3 more than that of train βAβ if both are running in opposite direction.Solution
Speed of train βAβ = 108 Γ (5/18) = 30 m/sec Length of train βAβ = 30 Γ 8 = 240 metres Length of train βBβ = 240 β 130 = 110 metres Speed of train βBβ = 30 + (30/3) = 40 m/sec Required time taken = (240 + 110)/(30 + 40) = 350/70 = 5 seconds
7(1/7)% of 3500 + 6(2/3)Β % of 6000 = ? + 552.5
What value should come in the place of (?) in the following questions.
336 Γ· 6 Γ· β16 * ? = 1400 Γ· 4
What will come in the place of question mark (?) in the given expression?
(18 Γ 8 + 24) Γ 4 = ?
Simplify the following expression:
Β Β (400 +175) Β² - (400 β 175) Β² / (400 Γ 175)
√(24²+285-8²-172) = ?²
26 X β25 + 15 - 80% of 120 = ?2Β
? = (22% of 25% of 60% of 3000) + 21

β? = 120 - 102 + β125