Question
1600 metres long train crosses a man who is moving in
the same direction with a certain speed in 25 seconds. If the same train can cross a pole in 20 seconds with the same speed, then find the speed of the man.Solution
Let the speed of the man be ‘x’ m/sec. Speed of train = 1600/20 = 80 m/sec Relative speed of the train = (80 – x) m/sec According to the question, => (80 – x) = 1600/25 => x = 80 – 64 => x = 16 Therefore the speed of the man = 16 m/sec
β323.89 Β Γ (3.20) Γ· 9.02 =?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
23.98% of 624.99 = 19.98% of ? + 14.98% of 639.99
Direction: Please solve the following expression and choose the closest option
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
12, 16, ?, 36, 52, 72Β
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(6859.01)1/3 Β Γ 10.11 Γ 14.47 Γ· 20.32 = ?Β + 45.022
33.33% of 809.891 + 66.66% of 212.91 = ?