Question
1440 metres long train crosses a man who is moving in
the same direction with a certain speed in 32 seconds. If the same train can cross a pole in 24 seconds with the same speed, then find the speed of the man.Solution
Let the speed of the man be βxβ m/sec. Speed of train = 1440/24 = 60 m/sec Relative speed of the train = (60 β x) m/sec According to the question, => (60 β x) = 1440/32 => x = 60 β 45 => x = 15 Therefore the speed of the man = 15 m/sec
6527.83 - 4891.21 + 7423.46 + ? = 14520.34
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? + 151.99 β 100.01 = 23.01 Γ 4.98
5555.05 + 500.05 + 5000.005 + 5.005 =?
Direction: Please solve the following expression and choose the closest option
? = 23.08 + 19.99 Γ 28.07
(25.032% of 48.05) X 9.32 + 43.125 X 3.125 - 29.67 =?
(56.03 + 112.98) Γ· 13.211 = 89.9 β 25.23% of ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....