Question
A train of length 540 metres crosses a man standing on platform in 18 seconds. If its speed decreases by 33⅓%, then find the time taken by train to cross a platform of length 660 metres.
Solution
Speed of train = (540 ÷ 18) = 30 m/s New speed of train = (2/3) × 30 = 20 m/s Required time = (540 + 660) ÷ 20
= 1200 ÷ 20
= 60 seconds
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