Question
A 360 m long train crosses a platform twice its length
in 2 min. Find the speed of the train.Solution
Speed of train = (Length of train + Length of Platform)/Required time Length of train = 360 m Crossing time of platform = 2 Ć 60 = 120 sec Length of platform = 360 Ć 2 = 720 m Let the speed of train be x. Speed of train = (360 + 720)/120 ā Ā x = 1080/120 = 9 m/s
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EKWYOT
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