Question
Ratio of the lengths of two trains ‘X’ and ‘Y’
is 4:5 respectively and the ratio of time taken by them to cross a pole is 3:4 respectively. If speed of train ‘X’ is 112 km/h, then find the speed of train ‘Y’.Solution
Speed of Train Y = 112 × (5/4) × (3/4) => 112 × 15/16 = 105 km/h
If {p2 + (2p2/5)} = 14p , p ≠ 0, then find the value of {p2 + (10/p) - 1}.
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- What number should be deducted from 45 and 30 so that their new ratio becomes 4:3?
