Question
A train can cross a pole in 33 seconds. While if the
train increased its speed by 40% then time taken by it to cross 387 metres long platform is 42 seconds. Find the time taken by the train to cross a 90 metre long tunnel.Solution
Let speed of train is βxβ m/s So, length of train = 33 Γ x = 33x metres And, 33x + 387 = 1.4 Γ x Γ 42 Or, 25.8x = 387 Or, x = 15 m/s So, length of train = 33 Γ 15 = 495 metres Desired time = (495 + 90)/15 = 39 seconds
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