Question
A civil contractor planned to build an over bridge of 3
km distance in 600 days. For this purpose, he employed 90 workers. After 200 days of work, it was observed that only 0.5 km of the bridge was completed. What is the number of extra workers required to complete the work on timeSolution
W1=1/6, W2=5/6 (M1 × D1× H1)/W1= (M2 × D2 × H2)/W2 (90 × 200)/1/6 = (M2 × 400)/5/6   M2 = 225  Þ Extra people = 225 – 90 = 135.
The "load factor" of a hash table is a critical metric. What does it represent?
Predict the output
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list2 = [1, 2, 3, 4, 5, 6, 7 ]
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