Question
A 420 m long train crosses a platform twice its length
in 3 min. Find the speed of the train. Section 1Solution
Speed of train = (Length of train + Length of Platform)/Required time Length of train = 420 m Crossing time of platform = 3 × 60 = 180 sec Length of platform = 420 × 2 = 840 m Let the speed of train be x. Speed of train = (420 + 840)/180 ⇒ x = 7 m/s
More Trains Questions
What will come in the place of question mark (?) in the given expression?
(√676 of √144 ÷ 13) of 2400% = ?
(47.5 ÷ 9.5) × (78.5 ÷ 15.7) + 475 = ? + 15% of 150
20% of (√9216 + ?) = 24
20 × 224 ÷ 16 – 50 = ? + 100
...144 (1/2) × 14 – 28 = 7 × ?
- What will come in place of the question mark (?) in the following questions?
75% of 240 + 30 = ? Simplify: 3/4 + {5/6 ÷ (2/3 − 1/6)} − 7/8
- What will come in place of (?) in the given expression.
(⅗ of 450) – (⅖ of 300) = ? 1555.5 + 1000.8 – 1354.3 = ? + 52
116 ÷ 280 of 1/2 + 3/5 × 5/3 = ?
