Question
'P' and 'Q' together can complete the work in 12 days.
'Q' alone can complete the work in 36 days. If R is 50% more efficient than P, find the time taken by 'R' alone to finish the work.Solution
Let the total work be 72 units
Combined efficiency of 'P' and 'Q' = (72/12) = 6 units/day
Efficiency of 'Q' alone = (72/36) = 2 units/day
Efficiency of 'P' alone = 6 - 2 = 4 units/day
Efficiency of 'R' = 4 × (3/2) = 6 units/day
Time taken by 'R' alone to finish the work = 72 ÷ 6 = 12 days
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