Question
A, B and C alone can complete a work in 24, 48 and 32
days respectively. All of them started working together but after 2 days from start A left the job and after 3 more days B also left the job. So for how many days did C work?Solution
Let the total work = 96 units (LCM of 24, 48 and 32) Amount of work done by A alone in one day = 96/24 = 4 units Amount of work done by B alone in one day = 96/48 = 2 units Amount of work done by C alone in one day = 96/32 = 3 units Amount of work done by A, B and C together in 2 days = 2 × (4 + 2 + 3) = 18 units Amount of work done by B and C together in 3 days = 3 × (2 + 3) = 15 units Remaining work = 96 – 18 – 15 = 63 units So, the time taken by C alone to complete 63 units work = 63/3 = 21 days So, C worked for 21 + 2 + 3 = 26 days
Statements: X & C, C % W, W $ S, S @ L
Conclusions: I. L & C II. S # C III. W @ X
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In the following question, a relationship between different elements is shown in the statements, followed by two conclusions I and II. Assuming the stat...
Given the following expression, find which of the equations from the given options is true ?
N ≥ P ≥ M ≥ U = D ≥ F
Statements:K < L,L ≥ M,M > N
Conclusions: I. K < M II. N > K
Statements: F @ R, R $ J, V % J, V # Z
Conclusions: I. F * V       II. R * V                              �...
Statements: H ≥ I < J ≥ K > L ≥ M
Conclusions:
I. L < J
II. M ≤ J
III. K ≥ J
IV. I = K
Statements: P < R = S = T < U < V; Q = V < W < X < O
Conclusions:
I. Q > R
II. P < OStatements: T = U > W < X ≤ Y ≥ V > Z > R = S
Conclusions:
I. T > V
II. T ≤ V
III. S > Y