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Start learning 50% faster. Sign in nowLet the total work = 288 units (LCM of 18, 32 and 24) Amount of work done by A alone in one day = 288/18 = 16 units Amount of work done by B alone in one day = 288/32 = 9 units Amount of work done by C alone in one day = 288/24 = 12 units Amount of work done by A, B and C together in 3 days = 3 × (16 + 9 + 12) = 111 units Amount of work done by B and C together in 5 days = 5 × (9 + 12) = 105 units Remaining work = 288 – 111 – 105 = 72 units So, the time taken by C alone to complete 72 units work = 72/12 = 6 days So, C worked for 6 + 3 + 5 = 14 days
The base of a prism is an equilateral triangle with a perimeter of 36 cm. If the height of the prism is 12 cm, calculate the volu...
(1.01) 0 + (2.02) 1 + (2.93) 2 + (4.04) 3 + (5.05) 4 = ?
(124.99)² = ?
6401.23 × `1 3/4` - 352.87 × ? = 10443.789
30.05% of 149.97 + ? X 8.88 = (39.95 + 12.012 - 13.0322)2
22.11 × 4.98 + 23.03 × 5.12 – 32.95 + 96.9 × 5.02 =?
70.14% of 799.95 - 240.12 = ? + 40.17% of 299.95
A salesman is allowed 32% commission on the total sales by him and a bonus of 3% on the sales over Rs. 15000. If the total earnings of a salesman is Rs....