Question
A can complete a work in 20 days, B in 30 days and C in
60 days. They work together for 5 days, then C leaves. In how many more days will A and B finish the remaining work?Solution
A+B+C rate = 1/20 + 1/30 + 1/60 = (3+2+1)/60 = 6/60 = 1/10 Work done in 5 days = 5*(1/10) = 1/2 Remaining work = 1/2 A+B rate = 1/20 + 1/30 = (3+2)/60 = 5/60 = 1/12 Time to finish remaining = (1/2) ÷ (1/12) = (1/2)*12 = 6 days Total time = 5 + 6 = 11 days Answer: 11 days
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