Question
A can finish a piece of work in 10 days and B can finish
it in 15 days. If both work together, in how many days will the work be completed?Solution
A’s 1-day work = 1/10 B’s 1-day work = 1/15 Combined 1-day work = 1/10 + 1/15 LCM(10, 15) = 30 = 3/30 + 2/30 = 5/30 = 1/6 Time required = 1 ÷ (1/6) = 6 days Answer: 6 days
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