Question
A alone can do a piece of work in 10 days and B alone in
15 days. In how many days will they finish the work together?Solution
ATQ, A's 1-day work = 1/10 B's 1-day work = 1/15 Together in 1 day = 1/10 + 1/15 LCM of 10 and 15 = 30 1/10 = 3/30, 1/15 = 2/30 Total = (3 + 2)/30 = 5/30 = 1/6 So time = 6 days
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