Question
βRβ and βSβ can together finish a job in 18
days. If βRβ alone can finish it in 30 days, how many days will βSβ alone take?Solution
ATQ, Let total work = LCM (18, 30) = 90 units. Combined efficiency of βRβ and βSβ = 90 Γ· 18 = 5 units/day Efficiency of βRβ = 90 Γ· 30 = 3 units/day Efficiency of βSβ = 5 - 3 = 2 units/day Time taken by βSβ alone = 90 Γ· 2 = 45 days
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