Question
‘R’ and ‘S’ can together finish a job in 18
days. If ‘R’ alone can finish it in 30 days, how many days will ‘S’ alone take?Solution
ATQ, Let total work = LCM (18, 30) = 90 units. Combined efficiency of ‘R’ and ‘S’ = 90 ÷ 18 = 5 units/day Efficiency of ‘R’ = 90 ÷ 30 = 3 units/day Efficiency of ‘S’ = 5 - 3 = 2 units/day Time taken by ‘S’ alone = 90 ÷ 2 = 45 days
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