Question
A alone can complete 60% of a work in 24 days while B
takes 20 days more than A to complete it. If B and C together can complete the work in 35 days, then find the time taken by C alone to complete the same work.Solution
Time taken by A alone to complete the entire work = 24/0.6 = 40 days Time taken by B alone to complete the entire work = 40 + 20 = 60 days Let the total work = L.C.M of 40, 60 and 35 = 840 units Then, efficiency of B = (840/60) = 14 units/day Combined efficiency of B and C = (840/35) = 24 units/day So, efficiency of C alone = 24 – 14 = 10 units/day So, time taken by C alone to complete the entire work = (840/10) = 84 days
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