Question
Aman and Bheema together can
finish 50% of a task in 12 days, while Chinky alone can finish 30% of the same task in 12 days. Determine the time required for Aman, Bheema, and Chinky together to complete the entire task.Solution
ATQ,
Time taken by ‘Aman’ and ‘Bheema’ together to complete the whole task = (12/0.5) = 24 days Time taken by ‘Chinky’ to complete the whole task = (12/0.30) = 40 days Let total task be 120 units {LCM of 24 and 40} Efficiency of ‘Aman’ and ‘Bheema’ together = (120/24) = 5 units/day Efficiency of ‘Chinky’ alone = (120/40) = 3 units/day Required time = 120/(5 + 3) = 15 days
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