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    Question

    Aman and Bheema together can

    finish 50% of a task in 12 days, while Chinky alone can finish 30% of the same task in 12 days. Determine the time required for Aman, Bheema, and Chinky together to complete the entire task.
    A 22 days Correct Answer Incorrect Answer
    B 15 days Correct Answer Incorrect Answer
    C 18 days Correct Answer Incorrect Answer
    D 28 days Correct Answer Incorrect Answer

    Solution

    ATQ,

    Time taken by ‘Aman’ and ‘Bheema’ together to complete the whole task = (12/0.5) = 24 days Time taken by ‘Chinky’ to complete the whole task = (12/0.30) = 40 days Let total task be 120 units {LCM of 24 and 40} Efficiency of ‘Aman’ and ‘Bheema’ together = (120/24) = 5 units/day Efficiency of ‘Chinky’ alone = (120/40) = 3 units/day Required time = 120/(5 + 3) = 15 days

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