Question
‘A’ alone can complete a work in 18 days. ‘B’
alone can complete the same work in 25 days. If ‘A’ and ‘B’ work together for 5 days, then the remaining work can be completed by ‘A’ alone in how many days?Solution
Let the total amount of work = 450 units {LCM of 18 and 25} Then, efficiency of ‘A’ = 450/18 = 25 units/day Efficiency of ‘B’ = 450/25 = 18 units/day Combined efficiency of ‘A’ and ‘B’ = 25 + 18 = 43 units/day Work completed by ‘A’ and ‘B’ together in 5 days = 5 × 43 = 215 units Remaining work = 450 – 215 = 235 units Time taken by ‘A’ alone to complete the remaining work = 235/25 = 9.4 days
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
28.95% of 924.78 + 1955% of 38.99 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
9.99% of 19.86% of 30.23% of (11999.84 × 9.68) = ?
29.98% of 549.99 = ? - 254.97 + 79.98% of 74.99
1131.98 + ? – 1125.04 = 1364.93 – 1168.01
98.999 x 99.001 + 640.856=?
What approximate value should come in the place of (?) in the following questions?
?3 -18.32 * 40.24 ÷ √399 = 200.79 + 105.78
...960.02 of 238.89 ÷ 144.01 of 79.97 = ?
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