Question
βAβ alone can complete a work in 18 days. βBβ
alone can complete the same work in 25 days. If βAβ and βBβ work together for 5 days, then the remaining work can be completed by βAβ alone in how many days?Solution
Let the total amount of work = 450 units {LCM of 18 and 25} Then, efficiency of βAβ = 450/18 = 25 units/day Efficiency of βBβ = 450/25 = 18 units/day Combined efficiency of βAβ and βBβ = 25 + 18 = 43 units/day Work completed by βAβ and βBβ together in 5 days = 5 Γ 43 = 215 units Remaining work = 450 β 215 = 235 units Time taken by βAβ alone to complete the remaining work = 235/25 = 9.4 days
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