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    Question

    тАШAтАЩ alone can complete a work in 50 hours. тАШAтАЩ

    started the work alone and left after working on it for 30 hours. If тАШBтАЩ completed the rest of the work in 20 hours then find the time taken by тАШAтАЩ and тАШBтАЩ together to complete the whole work.
    A 20 hours Correct Answer Incorrect Answer
    B 22 hours Correct Answer Incorrect Answer
    C 25 hours Correct Answer Incorrect Answer
    D 23 hours Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the total work = 200 units Then, efficiency of тАШAтАЩ = (200/50) = 4 units/hour Work completed by тАШAтАЩ alone in 30 hours = 4 ├Ч 30 = 120 units Remaining work = 200 тАУ 120 = 80 units So, efficiency of тАШBтАЩ = 80/20 = 4 units/hour Therefore, combined efficiency of тАШAтАЩ and тАШBтАЩ = 4 + 4 = 8 units/hour So, time taken by тАШAтАЩ and тАШBтАЩ together to complete the work = (200/8) = 25 hours

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