Question
A task can be completed in 15 days when Akash and Bittu
work together. Akash is 30% more efficient than Bittu. If both started the task separately and Akash stopped after working for 10 days, how many additional days would Bittu require to finish the remaining work?Solution
ATQ,
Let the efficiency of 'Bittu' be 'x' units/day So, efficiency of 'Akash' = x × 1.3 = '1.3x' units/day So, total work = (1.3x + x) × 15 = '34.5x' units Work done in 10 days = 10 × (1.3x + x) = '23x' units So, work remaining = 34.5x - 23x = '11.5x' units So, time taken by 'Bittu' to finish the remaining work = 11.5x ÷ x = 11.5 daysÂ
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