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    Question

    A task can be completed in 15 days when Akash and Bittu

    work together. Akash is 30% more efficient than Bittu. If both started the task separately and Akash stopped after working for 10 days, how many additional days would Bittu require to finish the remaining work?
    A 12.5 days Correct Answer Incorrect Answer
    B 11.5 days Correct Answer Incorrect Answer
    C 18.5 days Correct Answer Incorrect Answer
    D 16.5 days Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the efficiency of 'Bittu' be 'x' units/day So, efficiency of 'Akash' = x × 1.3 = '1.3x' units/day So, total work = (1.3x + x) × 15 = '34.5x' units Work done in 10 days = 10 × (1.3x + x) = '23x' units So, work remaining = 34.5x - 23x = '11.5x' units So, time taken by 'Bittu' to finish the remaining work = 11.5x ÷ x = 11.5 days 

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