Question
A, B, and C together can do a work alone in 18 days, 32 days, and 60 days respectively. A alone starts the work and work for 3 days and leaves the work, then B alone does the work for 8 days and leaves the work. If remaining work is done by C alone then for how many days has C worked?
Solution
Total work = LCM of 18, 32 and 60 = 1440 units Unit per day of A = 1440/18 = 80 Unit per day of B = 1440/32 = 45 Unit per day of C = 1440/60 = 24 Units of work done by A in 3 days = 80 × 3 = 240 units Units of work done by B in 8 days = 45 × 8 = 360 units Remaining work = 1440 – (240 + 360) = 840 units So, C has worked for 840/24 = 35 days
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