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    Question

    A, B, and C together can do a work alone in 12 days, 30

    days, and 60 days respectively. A alone starts the work and work for 3 days and leaves the work, then B alone does the work for 8 days and leaves the work. If remaining work is done by C alone then for how many days has C worked?
    A 29 days Correct Answer Incorrect Answer
    B 17.5 days Correct Answer Incorrect Answer
    C 39 days Correct Answer Incorrect Answer
    D 47 days Correct Answer Incorrect Answer
    E 56 days Correct Answer Incorrect Answer

    Solution

    Total work = LCM of 12, 30 and 60 = 60 units Unit per day of A = 60/12 = 5 Unit per day of B = 60/30 = 2 Unit per day of C = 60/60 = 1 Units of work done by A in 3 days = 5 × 3 = 15 units Units of work done by B in 8 days = 8 × 2 = 16 units Remaining work = 60 – (15 + 16) = 29 units So, C has worked for 29/1 = 29 days

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