Question
180 unit of work can be completed by P alone in 30 days.
P started working alone and joined by Q after 18 days such that they completed the remaining work in 6 days. Find the number of days taken by Q to complete the whole work alone.Solution
Let the efficiency of Q = x units/day Efficiency of P = (180/30) = 6 units/day According to question: 6 Γ 18 + (6 + x) Γ 6 = 180 Or, 108 + 36 + 6x = 180 Or, 6x = 180 β 144 Or, 6x = 36 Or, x = 6 Number of days taken by Q to complete the work alone = (180/6) = 30 days
375% of 320 - 80% of 40 Γ· β256 = ?
3 β(432 β 13 + 9 Γ 32) = ?
Evaluate:
β729 + β49 - β16 + 1/β64
[(11)2 - (12)2 + (5)3]2 = ?
(?) x 3 + 68 = β9025
0.25 x 696 Γ· 0.3 = ?
36.76 + 2894.713 + 34965.11 =?
What will come in the place of question mark (?) in the given expression?
?% of 2480 + 15 Γ 34 = 1440
I. 8xΒ² - 74x + 165 = 0
II. 15yΒ² - 38y + 24 = 0
What will come in the place of question mark (?) in the given expression?
28 Γ 15 + 48% of ? = 780