Question
A and B can do job in 8 days. B and C can do same job in
12 days. A, B and C together can do same job in 6 days. In how many days A and C together can complete the job?Solution
Total work = Number of days × 1 day’s work (efficiency) Total work = LCM (8, 12, 6) = 24 unit 1 day’s work of (A+B) = 24/8 = 3 unit 1 day’s work of (B + C) = 24/12 = 2 unit 1 day’s work of (A + B + C) = 24/6 = 4 unit Now, 1 day’s work of A = 4 – 2 = 2 1 day’s work of C = 4 – 3 = 1 1 day’s work of A and C = 2 + 1 = 3 A and C together can complete the job in = 24/3 = 8 days
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