Question
Abhay and Bhuvan working together can complete a sales
target in 24 days. Bhuvan and Chikku working together can finish the same sales target in 32 days. Abhay and Chikku working together can complete the sales target in 48 days. Determine the ratio of the number of days each of them individually takes to achieve the entire target.Solution
ATQ, Let total target achieved = 96 units Efficiency of (Abhay + Bhuvan) = 96/24 = 4 units/day Efficiency of (Bhuvan + Chikku) = 96/32 = 3 units/day Efficiency of (Abhay + Chikku) = 96/48 = 2 units/day Therefore, 2 × efficiency of (Abhay + Bhuvan + Chikku) = 9 units/day Or, efficiency of (Abhay + Bhuvan + Chikku) = 4.5 units/day Therefore, efficiency of ‘Chikku’ = 0.5 units/day Efficiency of ‘Abhay’ = 1.5 units/day Efficiency of ‘Bhuvan’ = 2.5 units/day Therefore, ratio of number of days taken by ‘Abhay’, ‘Bhuvan’ and ‘Chikku’, respectively = (1/1.5):(1/2.5):(1/0.5) = 5:3:15
Statements: A < B < E = C = F ≤ H ≤ G > L ≥ D
Conclusions:
I. H > A
II. G ≥ E
III. L > CStatements: M * T, D % T, D # K, K $ R
Conclusions: I. M * D II. T # K II...
Statements:
P < Q < R < S ≤ B < H; S > N ≥ Y
Conclusions:
I) P < Y
II) R ≥ N
Statements: Q > M ≤ F < H; V = A > M > P; Z < I < P
Conclusions:
I. H ≥ Z
II. I < Q
III. V = I
Which of the following should be placed in the blank spaces respectively ( in the same order from left to right) in order to complete the given express...
Statements: K ≥ N = I ≥ H ≤ U; B = S ≤ I
Conclusion: I. B < K II. B = K
Statements: V ≤R = W ≥ Q, U = T ≥ S < X, U < Q
Conclusions: I. S < W II. V ≥ X
Statements:
P ≥ Q = R; S = T ≤ U ≥ P
Conclusion:
I. R < S
II. T ≤ Q
Statements: E * M, M # N, N $ K
Conclusions: a) E * N b) M $ K
Statement:
R ≤ P >K ≤ L; W ≤ X = K > O; Q > L
Conclusion:
I) W < L
II) L = W
