Question
Working alone, B can complete the work in 30 days. C is
thrice as efficient as B and A takes 5 days more than it takes C to complete the work. Working together, in how much time would they be able to complete 4 such works?Solution
Time taken by B to complete the work = 30 days Time taken by C to complete the work = 30/3 = 10 days Time taken by A to complete the work alone = 10 + 5 = 15 days Work done by A, B and C together in 1 day. ⇒ (1/30 + 1/10 + 1/15) = (1 + 3 + 2)/30 = 6/30 this means if would take 30/6 days for A, B and C to complete the work together ∴ Time taken A, B and C to complete 4 works = 4 × 30/6 days = 20 days
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