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    Question

    A train service was disrupted due to an accident after a

    travel of 30 km. The speed was reduced to three-fourths of the original speed. This caused a delay of 45 min. If the accident had happened 18 km farther, it would have been running late for 36 min. What was the original speed of the train?
    A 50 km/h Correct Answer Incorrect Answer
    B 30 km/h Correct Answer Incorrect Answer
    C 60 km/h Correct Answer Incorrect Answer
    D 40 km/h Correct Answer Incorrect Answer

    Solution

    Let the speed of the train be x. We know that. ┬а Speed = Distance/Time Speed after accident = 3/4 of x = 3x/4 According to the question, The time difference in covering 18 km due to change in speed = 45 - 36 = 9 min 18/(3x/4) -(18/x) =9/60 72/3x)-18/x=9/60 ┬а x = 40 km/h ┬а The original speed of the train is 40 Km/h.

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