A can complete a work in 18 days. B takes 6 days less than A to complete the same work. In how many days can both of them together complete 50% of the work together?
Time taken by B to complete the work = 18 – 6 = 12 days Let the total work = 36 units Efficiency of A = 36/18 = 2 units/day Efficiency of B = 36/12 = 3 units/day Required time taken = 0.50 x 36/(2+3) = 3.6 days
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