Question
In a 1000-metre race, 'Ravi' beats 'Shyam' by '200'
metres and 'Raj' by '300' metres. If 'Shyam' and 'Raj' participate in a 400-metre race, and 'Raj' gets a head start of 35 metres, then find the distance between 'Shyam' and 'Raj' when the winner reaches the finish line.Solution
ATQ, Ratio of speeds of 'Ravi', 'Shyam', and 'Raj' = 1000 : (1000 - 200) : (1000 - 300) = 10 : 8 : 7 So, ratio of speeds of Shyam and Raj = 8 : 7 Distance covered by 'Raj' in the time taken by 'Shyam' to cover 400 metres = 400 × (7/8) = 350 metres Total difference between 'Shyam' and 'Raj' when 'Shyam' reaches the finish line = 400 - (350 + 35) = 15 metres So, 'Shyam' will beat 'Raj' by 15 metres.
(64/25)? × (125/512)?-1 = 5/8
(√121 + √196) × 7 =? × 5
- What will come in the place of question mark (?) in the given expression?
32% of 74% of ? = 16% of 37% of 180 2(3/4) of 2880 + 54% of 7520 - ? = 302
26 X √25 + 15 - 80% of 120 = ?2Â
- What will come in the place of question mark (?) in the given expression?
2850 ÷ 2.5 - ? × 42 = 300
12(3/5) + 4(1/5) × 3(2/3) =?
58% of 3300 - ?% of 2900 = 1740
[(4 √ (7) + √ (7)) × (7 √ (7) + 6 √ (7))] - 87 = ?
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