Question
In a 1000-metre race, 'Ravi' beats 'Shyam' by '200'
metres and 'Raj' by '300' metres. If 'Shyam' and 'Raj' participate in a 400-metre race, and 'Raj' gets a head start of 35 metres, then find the distance between 'Shyam' and 'Raj' when the winner reaches the finish line.Solution
ATQ, Ratio of speeds of 'Ravi', 'Shyam', and 'Raj' = 1000 : (1000 - 200) : (1000 - 300) = 10 : 8 : 7 So, ratio of speeds of Shyam and Raj = 8 : 7 Distance covered by 'Raj' in the time taken by 'Shyam' to cover 400 metres = 400 × (7/8) = 350 metres Total difference between 'Shyam' and 'Raj' when 'Shyam' reaches the finish line = 400 - (350 + 35) = 15 metres So, 'Shyam' will beat 'Raj' by 15 metres.
More Time and distance Questions
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
24.45% of 14.99% of 14999.78 + 159.80 = ?% of 1999.78
15.78% of (287 + 302) + 12³ = ?% of 170 + 8 × 14 + 3²
? = 65.78² ÷ (5.01⁵ + 7.02 × 33.33) + 33.33% of (290.88 × 23.09)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
1784.04 - 483.98 + 464.98 ÷ 15.06 = ?3
? = 54.89 × 270.08 ÷ 135.17 + 464.35 ÷ 29.03
233.98 + 73 × √35.95 - ? = 275.94 ÷ 3.99
