Question
Solution
= sin θ[(1 - tan θ) tan θ + sec2 θ] / (1 - sin θ)(tan θ)(1 + tan θ)(sec θ + tan θ) = sin θ[tan θ – tan2 θ + sec2 θ] / 1 - sin θ) (sin θ / cos θ) ( 1 + tan θ)(1 + sin θ / cos θ) = [tan θ + 1] / 1 – sin2 θ (1 + tan θ)1/cos2 θ = cos2 θ / cos2 θ = 1 Using (1 – sin θ)(1 + sin θ) = 12 – sin2 θ (a + b)(a – b) = a2 – b2
321, 240, ?, 105, 51, 6
14, 20, 29, 44, 65, ?
562, 628, 698, ?, 850
1, 7, 37, 187, 937, ?
What will come in the place of questions (?) mark in the following questions.
160, 223, 271, 306, 330, ?
250 Â Â Â 25 Â Â Â Â 5 Â Â Â Â ? Â Â Â Â 0.6 Â Â Â Â Â 0.3
7   4   5   9   20    ?    160.5
11          20          ?             64          112        192
...What will come in place of the question mark (?) in the following series?
10, 135, ?, 226, 234, 235
What will come in place of the question mark (?) in the following series?
5, 14, 41, 122, 365, 1094, ?
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