Question
Solution
= [[4 sin A cos3 A] – [4 cos A sin3 A]] / ฬถ s in 4 A = [4 sin A cos A [4 cos2 A sin2 A]] / ฬถ s in 4 A = 2 × 2 sin A cos A [cos 2A] / ฬถ s in 4 A = 2 × 2 sin2 A cos2 A / ฬถ s in 4 A = Sin 4A / - s in 4 A = ฬถ 1
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